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11x^2-216x+324=0
a = 11; b = -216; c = +324;
Δ = b2-4ac
Δ = -2162-4·11·324
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-216)-180}{2*11}=\frac{36}{22} =1+7/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-216)+180}{2*11}=\frac{396}{22} =18 $
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